Search a number
BaseRepresentation
bin11111110111000010111001…
…011000111111001100111101
3200101010112200200222001021222
4133313002321120333030331
5121331230102042244442
61214003114223203125
741341326562045034
oct3767027130771475
9611115620861258
10140122123399997
11407135057571a2
12138707337464a5
1360255c87b976b
142685d3865171b
15112ed70acc8d2
hex7f70b963f33d

140122123399997 has 2 divisors, whose sum is σ = 140122123399998. Its totient is φ = 140122123399996.

The previous prime is 140122123399987. The next prime is 140122123400053. The reversal of 140122123399997 is 799993321221041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 87070434971716 + 53051688428281 = 9331154^2 + 7283659^2 .

It is a cyclic number.

It is not a de Polignac number, because 140122123399997 - 212 = 140122123395901 is a prime.

It is a super-2 number, since 2×1401221233999972 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140122123399987) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70061061699998 + 70061061699999.

It is an arithmetic number, because the mean of its divisors is an integer number (70061061699999).

Almost surely, 2140122123399997 is an apocalyptic number.

It is an amenable number.

140122123399997 is a deficient number, since it is larger than the sum of its proper divisors (1).

140122123399997 is an equidigital number, since it uses as much as digits as its factorization.

140122123399997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13226976, while the sum is 62.

The spelling of 140122123399997 in words is "one hundred forty trillion, one hundred twenty-two billion, one hundred twenty-three million, three hundred ninety-nine thousand, nine hundred ninety-seven".