140122123400052 has 24 divisors (see below), whose sum is σ = 363279579185600. Its totient is φ = 46707374466648.

The previous prime is 140122123399997. The next prime is 140122123400053. The reversal of 140122123400052 is 250004321221041.

140122123400052 is a `hidden beast` number, since 1 + 40 + 1 + 2 + 212 + 3 + 400 + 0 + 5 + 2 = 666.

It is a super-2 number, since 2×140122123400052² (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 140122123399989 and 140122123400025.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140122123400053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 648713534152 + ... + 648713534367.

Almost surely, 2^{140122123400052} is an apocalyptic number.

140122123400052 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

140122123400052 is an abundant number, since it is smaller than the sum of its proper divisors (223157455785548).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

140122123400052 is a wasteful number, since it uses less digits than its factorization.

140122123400052 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1297427068532 (or 1297427068524 counting only the distinct ones).

The product of its (nonzero) digits is 3840, while the sum is 27.

Adding to 140122123400052 its reverse (250004321221041), we get a palindrome (390126444621093).

The spelling of 140122123400052 in words is "one hundred forty trillion, one hundred twenty-two billion, one hundred twenty-three million, four hundred thousand, fifty-two".