140122123400053 has 2 divisors, whose sum is σ = 140122123400054. Its totient is φ = 140122123400052.

The previous prime is 140122123399997. The next prime is 140122123400089. The reversal of 140122123400053 is 350004321221041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 125387634266244 + 14734489133809 = 11197662^2 + 3838553^2 .

It is a cyclic number.

It is not a de Polignac number, because 140122123400053 - 2⁹ = 140122123399541 is a prime.

It is a super-2 number, since 2×140122123400053² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 140122123399994 and 140122123400030.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140122123410053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70061061700026 + 70061061700027.

It is an arithmetic number, because the mean of its divisors is an integer number (70061061700027).

Almost surely, 2^{140122123400053} is an apocalyptic number.

It is an amenable number.

140122123400053 is a deficient number, since it is larger than the sum of its proper divisors (1).

140122123400053 is an equidigital number, since it uses as much as digits as its factorization.

140122123400053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 140122123400053 its reverse (350004321221041), we get a palindrome (490126444621094).

The spelling of 140122123400053 in words is "one hundred forty trillion, one hundred twenty-two billion, one hundred twenty-three million, four hundred thousand, fifty-three".