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14013022305 = 35934201487
BaseRepresentation
bin11010000110011110…
…11100000001100001
31100011120222021211010
431003033130001201
5212144313203210
610234255411133
71004153503302
oct150317340141
940146867733
1014013022305
115a40a93077
122870b23aa9
13142421b299
1496d1067a9
15570356920
hex3433dc061

14013022305 has 8 divisors (see below), whose sum is σ = 22420835712. Its totient is φ = 7473611888.

The previous prime is 14013022301. The next prime is 14013022307. The reversal of 14013022305 is 50322031041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14013022305 - 22 = 14013022301 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (14013022301) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 467100729 + ... + 467100758.

It is an arithmetic number, because the mean of its divisors is an integer number (2802604464).

Almost surely, 214013022305 is an apocalyptic number.

14013022305 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

14013022305 is a deficient number, since it is larger than the sum of its proper divisors (8407813407).

14013022305 is an equidigital number, since it uses as much as digits as its factorization.

14013022305 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 934201495.

The product of its (nonzero) digits is 720, while the sum is 21.

Adding to 14013022305 its reverse (50322031041), we get a palindrome (64335053346).

The spelling of 14013022305 in words is "fourteen billion, thirteen million, twenty-two thousand, three hundred five".

Divisors: 1 3 5 15 934201487 2802604461 4671007435 14013022305