Base | Representation |
---|---|
bin | 11010001011100001… |
… | …00100110100101011 |
3 | 1100021112110100212222 |
4 | 31011300210310223 |
5 | 212241121413111 |
6 | 10242405024255 |
7 | 1005205524461 |
oct | 150560446453 |
9 | 40245410788 |
10 | 14055263531 |
11 | 5a62914581 |
12 | 28830b508b |
13 | 142cbbacaa |
14 | 974980831 |
15 | 573dec7db |
hex | 345c24d2b |
14055263531 has 2 divisors, whose sum is σ = 14055263532. Its totient is φ = 14055263530.
The previous prime is 14055263513. The next prime is 14055263543. The reversal of 14055263531 is 13536255041.
Together with previous prime (14055263513) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14055263531 is a prime.
It is a super-2 number, since 2×140552635312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14055263491 and 14055263500.
It is not a weakly prime, because it can be changed into another prime (14055263581) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7027631765 + 7027631766.
It is an arithmetic number, because the mean of its divisors is an integer number (7027631766).
Almost surely, 214055263531 is an apocalyptic number.
14055263531 is a deficient number, since it is larger than the sum of its proper divisors (1).
14055263531 is an equidigital number, since it uses as much as digits as its factorization.
14055263531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54000, while the sum is 35.
The spelling of 14055263531 in words is "fourteen billion, fifty-five million, two hundred sixty-three thousand, five hundred thirty-one".
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