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14059998425437 is a prime number
BaseRepresentation
bin1100110010011001100100…
…1101100011000101011101
31211210010022110112202121121
43030212121031203011131
53320324334044103222
645523024001330541
72650541603506516
oct314463115430535
954703273482547
1014059998425437
1145308a2627758
1216b0b09036a51
137acb1027c533
14368716a31a0d
15195aed43e5c7
hexcc99936315d

14059998425437 has 2 divisors, whose sum is σ = 14059998425438. Its totient is φ = 14059998425436.

The previous prime is 14059998425411. The next prime is 14059998425483. The reversal of 14059998425437 is 73452489995041.

14059998425437 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12727384462116 + 1332613963321 = 3567546^2 + 1154389^2 .

It is an emirp because it is prime and its reverse (73452489995041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14059998425437 - 27 = 14059998425309 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14059998425237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7029999212718 + 7029999212719.

It is an arithmetic number, because the mean of its divisors is an integer number (7029999212719).

Almost surely, 214059998425437 is an apocalyptic number.

It is an amenable number.

14059998425437 is a deficient number, since it is larger than the sum of its proper divisors (1).

14059998425437 is an equidigital number, since it uses as much as digits as its factorization.

14059998425437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 391910400, while the sum is 70.

The spelling of 14059998425437 in words is "fourteen trillion, fifty-nine billion, nine hundred ninety-eight million, four hundred twenty-five thousand, four hundred thirty-seven".