14100113 has 2 divisors, whose sum is σ = 14100114.
Its totient is φ = 14100112.
The previous prime is 14100101. The next prime is 14100137. The reversal of 14100113 is 31100141.
Adding to 14100113 its reverse (31100141), we get a palindrome (45200254).
14100113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9909904 + 4190209 = 3148^2 + 2047^2
It is a cyclic number.
It is not a de Polignac number, because 14100113 - 28 = 14099857 is a prime.
It is a super-2 number, since 2×141001132 = 397626373225538, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14100094 and 14100103.
It is not a weakly prime, because it can be changed into another prime (14100143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7050056 + 7050057.
It is an arithmetic number, because the mean of its divisors is an integer number (7050057).
Almost surely, 214100113 is an apocalyptic number.
It is an amenable number.
14100113 is a deficient number, since it is larger than the sum of its proper divisors (1).
14100113 is an equidigital number, since it uses as much as digits as its factorization.
14100113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 11.
The square root of 14100113 is about 3755.0117176914.
The cubic root of 14100113 is about 241.5873542878.
The spelling of 14100113 in words is "fourteen million, one hundred thousand, one hundred thirteen".