14110000031 has 2 divisors, whose sum is σ = 14110000032. Its totient is φ = 14110000030.

The previous prime is 14110000027. The next prime is 14110000123. The reversal of 14110000031 is 13000001141.

It is a weak prime.

It is an emirp because it is prime and its reverse (13000001141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14110000031 - 2² = 14110000027 is a prime.

It is a super-2 number, since 2×14110000031² (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 14109999967 and 14110000021.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14110000231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7055000015 + 7055000016.

It is an arithmetic number, because the mean of its divisors is an integer number (7055000016).

Almost surely, 2^14110000031 is an apocalyptic number.

14110000031 is the 53123-rd centered decagonal number.

14110000031 is a deficient number, since it is larger than the sum of its proper divisors (1).

14110000031 is an equidigital number, since it uses as much as digits as its factorization.

14110000031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 14110000031 its reverse (13000001141), we get a palindrome (27110001172).

The spelling of 14110000031 in words is "fourteen billion, one hundred ten million, thirty-one", and thus it is an aban number.