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14111131 is a prime number
BaseRepresentation
bin110101110101…
…000110011011
3222112220211111
4311311012123
512103024011
61222241151
7230641216
oct65650633
928486744
1014111131
117a689a1
1248861b7
132c00ba8
141c3477d
15138b121
hexd7519b

14111131 has 2 divisors, whose sum is σ = 14111132. Its totient is φ = 14111130.

The previous prime is 14111113. The next prime is 14111143. The reversal of 14111131 is 13111141.

It is a happy number.

Together with previous prime (14111113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a m-pointer prime, because the next prime (14111143) can be obtained adding 14111131 to its product of digits (12).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14111131 - 213 = 14102939 is a prime.

It is a super-2 number, since 2×141111312 = 398248036198322, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14111161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7055565 + 7055566.

It is an arithmetic number, because the mean of its divisors is an integer number (7055566).

Almost surely, 214111131 is an apocalyptic number.

14111131 is a deficient number, since it is larger than the sum of its proper divisors (1).

14111131 is an equidigital number, since it uses as much as digits as its factorization.

14111131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 12, while the sum is 13.

The square root of 14111131 is about 3756.4785371409. The cubic root of 14111131 is about 241.6502643380.

Adding to 14111131 its reverse (13111141), we get a palindrome (27222272).

The spelling of 14111131 in words is "fourteen million, one hundred eleven thousand, one hundred thirty-one".