Base | Representation |
---|---|
bin | 1100110101011001101000… |
… | …1111111111100010001111 |
3 | 1211222001101120012000210202 |
4 | 3031112122033333202033 |
5 | 3322200431143413043 |
6 | 50002431543324115 |
7 | 2654345333135462 |
oct | 315263217774217 |
9 | 54861346160722 |
10 | 14111555451023 |
11 | 455074a18a108 |
12 | 16baab745063b |
13 | 7b4938789674 |
14 | 36b00806b2d9 |
15 | 1971198451b8 |
hex | cd59a3ff88f |
14111555451023 has 4 divisors (see below), whose sum is σ = 14941646948160. Its totient is φ = 13281463953888.
The previous prime is 14111555450987. The next prime is 14111555451073. The reversal of 14111555451023 is 32015455511141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14111555451023 - 212 = 14111555446927 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14111555451073) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 415045748543 + ... + 415045748576.
It is an arithmetic number, because the mean of its divisors is an integer number (3735411737040).
Almost surely, 214111555451023 is an apocalyptic number.
14111555451023 is a deficient number, since it is larger than the sum of its proper divisors (830091497137).
14111555451023 is an equidigital number, since it uses as much as digits as its factorization.
14111555451023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 830091497136.
The product of its (nonzero) digits is 60000, while the sum is 38.
The spelling of 14111555451023 in words is "fourteen trillion, one hundred eleven billion, five hundred fifty-five million, four hundred fifty-one thousand, twenty-three".
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