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14114013211 is a prime number
BaseRepresentation
bin11010010010100001…
…01100000000011011
31100102122000011022001
431021100230000123
5212401141410321
610252304141431
71006521063364
oct151120540033
940378004261
1014114013211
115a92aa1031
12289a907877
13143c11ab0c
1497c6b4b6b
15579154c91
hex34942c01b

14114013211 has 2 divisors, whose sum is σ = 14114013212. Its totient is φ = 14114013210.

The previous prime is 14114013163. The next prime is 14114013223. The reversal of 14114013211 is 11231041141.

It is a strong prime.

It is an emirp because it is prime and its reverse (11231041141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14114013211 - 213 = 14114005019 is a prime.

It is not a weakly prime, because it can be changed into another prime (14114013271) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7057006605 + 7057006606.

It is an arithmetic number, because the mean of its divisors is an integer number (7057006606).

Almost surely, 214114013211 is an apocalyptic number.

14114013211 is a deficient number, since it is larger than the sum of its proper divisors (1).

14114013211 is an equidigital number, since it uses as much as digits as its factorization.

14114013211 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 14114013211 its reverse (11231041141), we get a palindrome (25345054352).

The spelling of 14114013211 in words is "fourteen billion, one hundred fourteen million, thirteen thousand, two hundred eleven".