Base | Representation |
---|---|
bin | 11010010011010010… |
… | …01101010111110011 |
3 | 1100110002002202000120 |
4 | 31021221031113303 |
5 | 212404313110311 |
6 | 10253054021323 |
7 | 1006626525303 |
oct | 151151152763 |
9 | 40402082016 |
10 | 14120441331 |
11 | 5a96691627 |
12 | 28a0aa7843 |
13 | 144055b939 |
14 | 97d4a9603 |
15 | 5799c4706 |
hex | 349a4d5f3 |
14120441331 has 4 divisors (see below), whose sum is σ = 18827255112. Its totient is φ = 9413627552.
The previous prime is 14120441323. The next prime is 14120441431. The reversal of 14120441331 is 13314402141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14120441331 - 23 = 14120441323 is a prime.
It is a super-2 number, since 2×141204413312 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (14120441431) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2353406886 + ... + 2353406891.
It is an arithmetic number, because the mean of its divisors is an integer number (4706813778).
Almost surely, 214120441331 is an apocalyptic number.
14120441331 is a deficient number, since it is larger than the sum of its proper divisors (4706813781).
14120441331 is an equidigital number, since it uses as much as digits as its factorization.
14120441331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4706813780.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 14120441331 its reverse (13314402141), we get a palindrome (27434843472).
The spelling of 14120441331 in words is "fourteen billion, one hundred twenty million, four hundred forty-one thousand, three hundred thirty-one".
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