14131113 has 4 divisors (see below), whose sum is σ = 18841488. Its totient is φ = 9420740.

The previous prime is 14131109. The next prime is 14131123. The reversal of 14131113 is 31113141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14131113 - 2² = 14131109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14131092 and 14131101.

It is not an unprimeable number, because it can be changed into a prime (14131123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2355183 + ... + 2355188.

It is an arithmetic number, because the mean of its divisors is an integer number (4710372).

Almost surely, 2^14131113 is an apocalyptic number.

It is an amenable number.

14131113 is a deficient number, since it is larger than the sum of its proper divisors (4710375).

14131113 is an equidigital number, since it uses as much as digits as its factorization.

14131113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4710374.

The product of its digits is 36, while the sum is 15.

The square root of 14131113 is about 3759.1372680444. The cubic root of 14131113 is about 241.7642731105.

Adding to 14131113 its reverse (31113141), we get a palindrome (45244254).

The spelling of 14131113 in words is "fourteen million, one hundred thirty-one thousand, one hundred thirteen".