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141323130034 = 270661565017
BaseRepresentation
bin1000001110011110000…
…0111101010010110010
3111111210001101211221021
42003213200331102302
54303412210130114
6144531205050054
713132055533162
oct2034740752262
9444701354837
10141323130034
1154a3124a339
12234809b692a
1310432a37c88
146ba92505a2
153a21e80024
hex20e783d4b2

141323130034 has 4 divisors (see below), whose sum is σ = 211984695054. Its totient is φ = 70661565016.

The previous prime is 141323130031. The next prime is 141323130043. The reversal of 141323130034 is 430031323141.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 132077730625 + 9245399409 = 363425^2 + 96153^2 .

It is a junction number, because it is equal to n+sod(n) for n = 141323129990 and 141323130008.

It is not an unprimeable number, because it can be changed into a prime (141323130031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35330782507 + ... + 35330782510.

Almost surely, 2141323130034 is an apocalyptic number.

141323130034 is a deficient number, since it is larger than the sum of its proper divisors (70661565020).

141323130034 is an equidigital number, since it uses as much as digits as its factorization.

141323130034 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 70661565019.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 141323130034 its reverse (430031323141), we get a palindrome (571354453175).

The spelling of 141323130034 in words is "one hundred forty-one billion, three hundred twenty-three million, one hundred thirty thousand, thirty-four".

Divisors: 1 2 70661565017 141323130034