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141332001301 = 419337307879
BaseRepresentation
bin1000001110100000001…
…0110011001000010101
3111111210200002120000201
42003220002303020111
54303421443020201
6144532123140501
713132224122011
oct2035002631025
9444720076021
10141332001301
1154a36259467
1223483974731
1310434822b4a
146baa4bd541
153a22b33801
hex20e80b3215

141332001301 has 4 divisors (see below), whose sum is σ = 141669309600. Its totient is φ = 140994693004.

The previous prime is 141332001299. The next prime is 141332001319. The reversal of 141332001301 is 103100233141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 141332001301 - 21 = 141332001299 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141332001331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 168653521 + ... + 168654358.

It is an arithmetic number, because the mean of its divisors is an integer number (35417327400).

Almost surely, 2141332001301 is an apocalyptic number.

It is an amenable number.

141332001301 is a deficient number, since it is larger than the sum of its proper divisors (337308299).

141332001301 is an equidigital number, since it uses as much as digits as its factorization.

141332001301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 337308298.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 141332001301 its reverse (103100233141), we get a palindrome (244432234442).

The spelling of 141332001301 in words is "one hundred forty-one billion, three hundred thirty-two million, one thousand, three hundred one".

Divisors: 1 419 337307879 141332001301