Base | Representation |
---|---|
bin | 11010011110010100… |
… | …10010110011101001 |
3 | 1100200112021020020011 |
4 | 31033022102303221 |
5 | 213102012003200 |
6 | 10310201531521 |
7 | 1012132340011 |
oct | 151712226351 |
9 | 40615236204 |
10 | 14213000425 |
11 | 6033960648 |
12 | 2907aa3ba1 |
13 | 1456798630 |
14 | 98b8c0c41 |
15 | 582ba95ba |
hex | 34f292ce9 |
14213000425 has 24 divisors (see below), whose sum is σ = 18985859480. Its totient is φ = 10492416000.
The previous prime is 14213000413. The next prime is 14213000453. The reversal of 14213000425 is 52400031241.
It can be written as a sum of positive squares in 12 ways, for example, as 8891735616 + 5321264809 = 94296^2 + 72947^2 .
It is not a de Polignac number, because 14213000425 - 25 = 14213000393 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14213000396 and 14213000405.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1555771 + ... + 1564879.
Almost surely, 214213000425 is an apocalyptic number.
It is an amenable number.
14213000425 is a deficient number, since it is larger than the sum of its proper divisors (4772859055).
14213000425 is a wasteful number, since it uses less digits than its factorization.
With its successor (14213000426) it forms an eRAP, since the sums of their prime factors are consecutive (13933 and 13934).
14213000425 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13933 (or 13928 counting only the distinct ones).
The product of its (nonzero) digits is 960, while the sum is 22.
Adding to 14213000425 its reverse (52400031241), we get a palindrome (66613031666).
The spelling of 14213000425 in words is "fourteen billion, two hundred thirteen million, four hundred twenty-five", and thus it is an aban number.
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