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14213000425 = 521348019109
BaseRepresentation
bin11010011110010100…
…10010110011101001
31100200112021020020011
431033022102303221
5213102012003200
610310201531521
71012132340011
oct151712226351
940615236204
1014213000425
116033960648
122907aa3ba1
131456798630
1498b8c0c41
15582ba95ba
hex34f292ce9

14213000425 has 24 divisors (see below), whose sum is σ = 18985859480. Its totient is φ = 10492416000.

The previous prime is 14213000413. The next prime is 14213000453. The reversal of 14213000425 is 52400031241.

It can be written as a sum of positive squares in 12 ways, for example, as 8891735616 + 5321264809 = 94296^2 + 72947^2 .

It is not a de Polignac number, because 14213000425 - 25 = 14213000393 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14213000396 and 14213000405.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1555771 + ... + 1564879.

Almost surely, 214213000425 is an apocalyptic number.

It is an amenable number.

14213000425 is a deficient number, since it is larger than the sum of its proper divisors (4772859055).

14213000425 is a wasteful number, since it uses less digits than its factorization.

With its successor (14213000426) it forms an eRAP, since the sums of their prime factors are consecutive (13933 and 13934).

14213000425 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13933 (or 13928 counting only the distinct ones).

The product of its (nonzero) digits is 960, while the sum is 22.

Adding to 14213000425 its reverse (52400031241), we get a palindrome (66613031666).

The spelling of 14213000425 in words is "fourteen billion, two hundred thirteen million, four hundred twenty-five", and thus it is an aban number.

Divisors: 1 5 13 25 65 325 4801 9109 24005 45545 62413 118417 120025 227725 312065 592085 1560325 2960425 43732309 218661545 568520017 1093307725 2842600085 14213000425