Base | Representation |
---|---|
bin | 1100111011010101000101… |
… | …0100000100111111101111 |
3 | 1212022210022001101001010212 |
4 | 3032311101110010333233 |
5 | 3330333031204002203 |
6 | 50121314553253035 |
7 | 2664612401050604 |
oct | 316652124047757 |
9 | 55283261331125 |
10 | 14213411000303 |
11 | 458a967a6a909 |
12 | 17167a270417b |
13 | 7c141b838358 |
14 | 371d0b7046ab |
15 | 199acb90c1d8 |
hex | ced51504fef |
14213411000303 has 8 divisors (see below), whose sum is σ = 14671225212336. Its totient is φ = 13760889438400.
The previous prime is 14213411000263. The next prime is 14213411000311. The reversal of 14213411000303 is 30300011431241.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14213411000303 - 212 = 14213410996207 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14213411000203) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1323157076 + ... + 1323167817.
It is an arithmetic number, because the mean of its divisors is an integer number (1833903151542).
Almost surely, 214213411000303 is an apocalyptic number.
14213411000303 is a deficient number, since it is larger than the sum of its proper divisors (457814212033).
14213411000303 is a wasteful number, since it uses less digits than its factorization.
14213411000303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2646325065.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 14213411000303 its reverse (30300011431241), we get a palindrome (44513422431544).
The spelling of 14213411000303 in words is "fourteen trillion, two hundred thirteen billion, four hundred eleven million, three hundred three", and thus it is an aban number.
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