Base | Representation |
---|---|
bin | 1000010001100100000… |
… | …0010010111001111001 |
3 | 111120220220202101110001 |
4 | 2010121000102321321 |
5 | 4312112234203401 |
6 | 145145425153001 |
7 | 13161460130542 |
oct | 2043100227171 |
9 | 446826671401 |
10 | 142153428601 |
11 | 553179a49a8 |
12 | 23672a8b761 |
13 | 10535a689c2 |
14 | 6c476254c9 |
15 | 3a6ecde601 |
hex | 2119012e79 |
142153428601 has 4 divisors (see below), whose sum is σ = 146739023104. Its totient is φ = 137567834100.
The previous prime is 142153428577. The next prime is 142153428611. The reversal of 142153428601 is 106824351241.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 142153428601 - 25 = 142153428569 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (142153428611) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2292797205 + ... + 2292797266.
It is an arithmetic number, because the mean of its divisors is an integer number (36684755776).
Almost surely, 2142153428601 is an apocalyptic number.
It is an amenable number.
142153428601 is a deficient number, since it is larger than the sum of its proper divisors (4585594503).
142153428601 is an equidigital number, since it uses as much as digits as its factorization.
142153428601 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4585594502.
The product of its (nonzero) digits is 46080, while the sum is 37.
Adding to 142153428601 its reverse (106824351241), we get a palindrome (248977779842).
The spelling of 142153428601 in words is "one hundred forty-two billion, one hundred fifty-three million, four hundred twenty-eight thousand, six hundred one".
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