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1424431135409 is a prime number
BaseRepresentation
bin10100101110100110101…
…101100011101010110001
312001011201001111001202212
4110232212231203222301
5141314213332313114
63010212530421505
7204624505610042
oct24564655435261
95034631431685
101424431135409
114aa109271997
121b0093131895
13a4428326509
144cd2b1d28c9
15270bce14b3e
hex14ba6b63ab1

1424431135409 has 2 divisors, whose sum is σ = 1424431135410. Its totient is φ = 1424431135408.

The previous prime is 1424431135357. The next prime is 1424431135451. The reversal of 1424431135409 is 9045311344241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1309800136225 + 114630999184 = 1144465^2 + 338572^2 .

It is a cyclic number.

It is not a de Polignac number, because 1424431135409 - 236 = 1355711658673 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (1424431132409) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 712215567704 + 712215567705.

It is an arithmetic number, because the mean of its divisors is an integer number (712215567705).

Almost surely, 21424431135409 is an apocalyptic number.

It is an amenable number.

1424431135409 is a deficient number, since it is larger than the sum of its proper divisors (1).

1424431135409 is an equidigital number, since it uses as much as digits as its factorization.

1424431135409 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 207360, while the sum is 41.

The spelling of 1424431135409 in words is "one trillion, four hundred twenty-four billion, four hundred thirty-one million, one hundred thirty-five thousand, four hundred nine".