Search a number
-
+
143112440423 = 831717207219
BaseRepresentation
bin1000010101001000101…
…0101000101001100111
3111200101202022020100102
42011102022220221213
54321043241043143
6145424524134315
713224313446431
oct2052212505147
9450352266312
10143112440423
115576a272757
12238a009739b
1310659654614
146cd8b43651
153ac90c60b8
hex21522a8a67

143112440423 has 4 divisors (see below), whose sum is σ = 143129655960. Its totient is φ = 143095224888.

The previous prime is 143112440417. The next prime is 143112440477. The reversal of 143112440423 is 324044211341.

Adding to 143112440423 its reverse (324044211341), we get a palindrome (467156651764).

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 324044211341 = 1392331253319.

It is a cyclic number.

It is not a de Polignac number, because 143112440423 - 220 = 143111391847 is a prime.

It is a super-3 number, since 3×1431124404233 (a number of 34 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (143112460423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8595293 + ... + 8611926.

It is an arithmetic number, because the mean of its divisors is an integer number (35782413990).

Almost surely, 2143112440423 is an apocalyptic number.

143112440423 is a deficient number, since it is larger than the sum of its proper divisors (17215537).

143112440423 is an equidigital number, since it uses as much as digits as its factorization.

143112440423 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17215536.

The product of its (nonzero) digits is 9216, while the sum is 29.

The spelling of 143112440423 in words is "one hundred forty-three billion, one hundred twelve million, four hundred forty thousand, four hundred twenty-three".

Divisors: 1 8317 17207219 143112440423