Base | Representation |
---|---|
bin | 11010101010010000… |
… | …01001101100010100 |
3 | 1100221111121220220121 |
4 | 31111020021230110 |
5 | 213303123231400 |
6 | 10324135241324 |
7 | 1014456234433 |
oct | 152510115424 |
9 | 40844556817 |
10 | 14313102100 |
11 | 6085411500 |
12 | 2935519244 |
13 | 14714464ab |
14 | 99acdb11a |
15 | 58b87e21a |
hex | 355209b14 |
14313102100 has 54 divisors (see below), whose sum is σ = 34139734622. Its totient is φ = 5204760000.
The previous prime is 14313102073. The next prime is 14313102107. The reversal of 14313102100 is 120131341.
It can be written as a sum of positive squares in 3 ways, for example, as 789272836 + 13523829264 = 28094^2 + 116292^2 .
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14313102107) by changing a digit.
It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 579351 + ... + 603550.
Almost surely, 214313102100 is an apocalyptic number.
14313102100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
14313102100 is an abundant number, since it is smaller than the sum of its proper divisors (19826632522).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14313102100 is a wasteful number, since it uses less digits than its factorization.
14313102100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1182937 (or 1182919 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 14313102100 its reverse (120131341), we get a palindrome (14433233441).
The spelling of 14313102100 in words is "fourteen billion, three hundred thirteen million, one hundred two thousand, one hundred".
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