1431344002001 has 4 divisors (see below), whose sum is σ = 1440823101504. Its totient is φ = 1421864902500.

The previous prime is 1431344001937. The next prime is 1431344002003. The reversal of 1431344002001 is 1002004431341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1431344002001 - 2⁶ = 1431344001937 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1431344002003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4739549525 + ... + 4739549826.

It is an arithmetic number, because the mean of its divisors is an integer number (360205775376).

Almost surely, 2^{1431344002001} is an apocalyptic number.

It is an amenable number.

1431344002001 is a deficient number, since it is larger than the sum of its proper divisors (9479099503).

1431344002001 is an equidigital number, since it uses as much as digits as its factorization.

1431344002001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9479099502.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 1431344002001 its reverse (1002004431341), we get a palindrome (2433348433342).

The spelling of 1431344002001 in words is "one trillion, four hundred thirty-one billion, three hundred forty-four million, two thousand, one".