Base | Representation |
---|---|
bin | 11010110000001101… |
… | …00000000000000001 |
3 | 1101001222112001002211 |
4 | 31120012200000001 |
5 | 213403412011313 |
6 | 10333120542121 |
7 | 1015633330666 |
oct | 153006400001 |
9 | 41058461084 |
10 | 14363000833 |
11 | 61005a3125 |
12 | 294a181941 |
13 | 147b89777c |
14 | 9a37a9a6d |
15 | 590e38e3d |
hex | 3581a0001 |
14363000833 has 4 divisors (see below), whose sum is σ = 14409786160. Its totient is φ = 14316215508.
The previous prime is 14363000819. The next prime is 14363000837. The reversal of 14363000833 is 33800036341.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 14363000833 - 221 = 14360903681 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14363000795 and 14363000804.
It is not an unprimeable number, because it can be changed into a prime (14363000837) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23392203 + ... + 23392816.
It is an arithmetic number, because the mean of its divisors is an integer number (3602446540).
It is a Proth number, since it is equal to 109581 ⋅ 217 + 1 and 109581 < 217.
Almost surely, 214363000833 is an apocalyptic number.
It is an amenable number.
14363000833 is a deficient number, since it is larger than the sum of its proper divisors (46785327).
14363000833 is an equidigital number, since it uses as much as digits as its factorization.
14363000833 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 46785326.
The product of its (nonzero) digits is 15552, while the sum is 31.
The spelling of 14363000833 in words is "fourteen billion, three hundred sixty-three million, eight hundred thirty-three", and thus it is an aban number.
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