Base | Representation |
---|---|
bin | 11010110100101001… |
… | …11010000101001111 |
3 | 1101011120202122222202 |
4 | 31122110322011033 |
5 | 213442441111421 |
6 | 10340533032115 |
7 | 1016565542354 |
oct | 153224720517 |
9 | 41146678882 |
10 | 14400332111 |
11 | 611a680720 |
12 | 295a78563b |
13 | 1486538699 |
14 | 9a872662b |
15 | 59436010b |
hex | 35a53a14f |
14400332111 has 4 divisors (see below), whose sum is σ = 15709453224. Its totient is φ = 13091211000.
The previous prime is 14400332059. The next prime is 14400332117. The reversal of 14400332111 is 11123300441.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14400332111 - 222 = 14396137807 is a prime.
It is a super-3 number, since 3×144003321113 (a number of 31 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14400332117) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 654560540 + ... + 654560561.
It is an arithmetic number, because the mean of its divisors is an integer number (3927363306).
Almost surely, 214400332111 is an apocalyptic number.
14400332111 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
14400332111 is a deficient number, since it is larger than the sum of its proper divisors (1309121113).
14400332111 is a wasteful number, since it uses less digits than its factorization.
14400332111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1309121112.
The product of its (nonzero) digits is 288, while the sum is 20.
Adding to 14400332111 its reverse (11123300441), we get a palindrome (25523632552).
The spelling of 14400332111 in words is "fourteen billion, four hundred million, three hundred thirty-two thousand, one hundred eleven".
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