Base | Representation |
---|---|
bin | 1101000110010000000001… |
… | …1001011001101111110111 |
3 | 1212222201120200101111010001 |
4 | 3101210000121121233313 |
5 | 3341421303143040201 |
6 | 50343424234412131 |
7 | 3014303666211265 |
oct | 321440031315767 |
9 | 55881520344101 |
10 | 14401032002551 |
11 | 4652497149857 |
12 | 1747024591047 |
13 | 80601c325a8c |
14 | 37b02970d435 |
15 | 19e90d1ea301 |
hex | d1900659bf7 |
14401032002551 has 2 divisors, whose sum is σ = 14401032002552. Its totient is φ = 14401032002550.
The previous prime is 14401032002477. The next prime is 14401032002563. The reversal of 14401032002551 is 15520023010441.
14401032002551 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14401032002551 - 213 = 14401031994359 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14401012002551) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7200516001275 + 7200516001276.
It is an arithmetic number, because the mean of its divisors is an integer number (7200516001276).
Almost surely, 214401032002551 is an apocalyptic number.
14401032002551 is a deficient number, since it is larger than the sum of its proper divisors (1).
14401032002551 is an equidigital number, since it uses as much as digits as its factorization.
14401032002551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4800, while the sum is 28.
Adding to 14401032002551 its reverse (15520023010441), we get a palindrome (29921055012992).
The spelling of 14401032002551 in words is "fourteen trillion, four hundred one billion, thirty-two million, two thousand, five hundred fifty-one".
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