14433121132 has 12 divisors (see below), whose sum is σ = 25267888800. Its totient is φ = 7213724336.

The previous prime is 14433121117. The next prime is 14433121133. The reversal of 14433121132 is 23112133441.

It is a super-2 number, since 2×14433121132² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14433121097 and 14433121106.

It is not an unprimeable number, because it can be changed into a prime (14433121133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 697588 + ... + 717979.

It is an arithmetic number, because the mean of its divisors is an integer number (2105657400).

Almost surely, 2^14433121132 is an apocalyptic number.

It is an amenable number.

14433121132 is a deficient number, since it is larger than the sum of its proper divisors (10834767668).

14433121132 is a wasteful number, since it uses less digits than its factorization.

14433121132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1418120 (or 1418118 counting only the distinct ones).

The product of its digits is 1728, while the sum is 25.

Adding to 14433121132 its reverse (23112133441), we get a palindrome (37545254573).

The spelling of 14433121132 in words is "fourteen billion, four hundred thirty-three million, one hundred twenty-one thousand, one hundred thirty-two".