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144333444402197 is a prime number
BaseRepresentation
bin100000110100010100111111…
…101011101100110000010101
3200221001010211220101221012022
4200310110333223230300111
5122404224343231332242
61230545511411502525
742254514205662401
oct4064247753546025
9627033756357168
10144333444402197
1141a97519666526
12142309565b7a45
13626c77c1a111b
14278dac1422101
1511a469dd580d2
hex83453faecc15

144333444402197 has 2 divisors, whose sum is σ = 144333444402198. Its totient is φ = 144333444402196.

The previous prime is 144333444402193. The next prime is 144333444402227. The reversal of 144333444402197 is 791204444333441.

144333444402197 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 99006201434596 + 45327242967601 = 9950186^2 + 6732551^2 .

It is a cyclic number.

It is not a de Polignac number, because 144333444402197 - 22 = 144333444402193 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (144333444402193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72166722201098 + 72166722201099.

It is an arithmetic number, because the mean of its divisors is an integer number (72166722201099).

Almost surely, 2144333444402197 is an apocalyptic number.

It is an amenable number.

144333444402197 is a deficient number, since it is larger than the sum of its proper divisors (1).

144333444402197 is an equidigital number, since it uses as much as digits as its factorization.

144333444402197 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13934592, while the sum is 53.

The spelling of 144333444402197 in words is "one hundred forty-four trillion, three hundred thirty-three billion, four hundred forty-four million, four hundred two thousand, one hundred ninety-seven".