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144413001211 = 606723803033
BaseRepresentation
bin1000011001111110101…
…1111000010111111011
3111210202101112120100111
42012133223320113323
54331224212014321
6150201543445151
713301455154023
oct2063753702773
9453671476314
10144413001211
1156277413286
1223ba37567b7
1310805c2790b
146dbd76ca83
153b533775e1
hex219faf85fb

144413001211 has 4 divisors (see below), whose sum is σ = 144436810312. Its totient is φ = 144389192112.

The previous prime is 144413001163. The next prime is 144413001217. The reversal of 144413001211 is 112100314441.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 144413001211 - 237 = 6974047739 is a prime.

It is a super-2 number, since 2×1444130012112 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (144413001217) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11895450 + ... + 11907583.

It is an arithmetic number, because the mean of its divisors is an integer number (36109202578).

Almost surely, 2144413001211 is an apocalyptic number.

144413001211 is a deficient number, since it is larger than the sum of its proper divisors (23809101).

144413001211 is an equidigital number, since it uses as much as digits as its factorization.

144413001211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23809100.

The product of its (nonzero) digits is 384, while the sum is 22.

Adding to 144413001211 its reverse (112100314441), we get a palindrome (256513315652).

The spelling of 144413001211 in words is "one hundred forty-four billion, four hundred thirteen million, one thousand, two hundred eleven".

Divisors: 1 6067 23803033 144413001211