Search a number
148531157773 is a prime number
BaseRepresentation
bin1000101001010100100…
…1011001101100001101
3112012101101120121010121
42022111021121230031
54413142434022043
6152122334104541
713505512003255
oct2122511315415
9465341517117
10148531157773
1157a9aa6a259
122495294b151
131101117914b
14729067c965
153ce4b8bded
hex2295259b0d

148531157773 has 2 divisors, whose sum is σ = 148531157774. Its totient is φ = 148531157772.

The previous prime is 148531157771. The next prime is 148531157807. The reversal of 148531157773 is 377751135841.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 82413778084 + 66117379689 = 287078^2 + 257133^2 .

It is a cyclic number.

It is not a de Polignac number, because 148531157773 - 21 = 148531157771 is a prime.

Together with 148531157771, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 148531157773.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (148531157771) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 74265578886 + 74265578887.

It is an arithmetic number, because the mean of its divisors is an integer number (74265578887).

Almost surely, 2148531157773 is an apocalyptic number.

It is an amenable number.

148531157773 is a deficient number, since it is larger than the sum of its proper divisors (1).

148531157773 is an equidigital number, since it uses as much as digits as its factorization.

148531157773 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2469600, while the sum is 52.

The spelling of 148531157773 in words is "one hundred forty-eight billion, five hundred thirty-one million, one hundred fifty-seven thousand, seven hundred seventy-three".