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149245791245 = 529849158249
BaseRepresentation
bin1000101011111110111…
…1100000110000001101
3112021020012021201221222
42022333233200300031
54421123410304440
6152321303133125
713532310202625
oct2127757406015
9467205251858
10149245791245
11583273a3a31
1224b121441a5
13110c62400a5
14731b545885
153d377a02b5
hex22bfbe0c0d

149245791245 has 4 divisors (see below), whose sum is σ = 179094949500. Its totient is φ = 119396632992.

The previous prime is 149245791239. The next prime is 149245791257. The reversal of 149245791245 is 542197542941.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 542197542941 = 3904113887901.

It can be written as a sum of positive squares in 2 ways, for example, as 66309855049 + 82935936196 = 257507^2 + 287986^2 .

It is a cyclic number.

It is not a de Polignac number, because 149245791245 - 212 = 149245787149 is a prime.

It is a super-2 number, since 2×1492457912452 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14924579120 + ... + 14924579129.

It is an arithmetic number, because the mean of its divisors is an integer number (44773737375).

Almost surely, 2149245791245 is an apocalyptic number.

It is an amenable number.

149245791245 is a deficient number, since it is larger than the sum of its proper divisors (29849158255).

149245791245 is an equidigital number, since it uses as much as digits as its factorization.

149245791245 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 29849158254.

The product of its digits is 3628800, while the sum is 53.

The spelling of 149245791245 in words is "one hundred forty-nine billion, two hundred forty-five million, seven hundred ninety-one thousand, two hundred forty-five".

Divisors: 1 5 29849158249 149245791245