Base | Representation |
---|---|
bin | 1101101111101001100001… |
… | …1110010111010110110001 |
3 | 1222111201100220020212011002 |
4 | 3123322120132113112301 |
5 | 3440044343234403040 |
6 | 52050250113531345 |
7 | 3116552501262635 |
oct | 333723036272661 |
9 | 58451326225132 |
10 | 15112253044145 |
11 | 48a7085960044 |
12 | 1840a32b73b55 |
13 | 858105430baa |
14 | 3a3618dc2dc5 |
15 | 1b3187455a15 |
hex | dbe987975b1 |
15112253044145 has 8 divisors (see below), whose sum is σ = 18139799123520. Its totient is φ = 12086405454960.
The previous prime is 15112253044103. The next prime is 15112253044193. The reversal of 15112253044145 is 54144035221151.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 15112253044145 - 220 = 15112251995569 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 15112253044099 and 15112253044108.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 424602971 + ... + 424638560.
It is an arithmetic number, because the mean of its divisors is an integer number (2267474890440).
Almost surely, 215112253044145 is an apocalyptic number.
It is an amenable number.
15112253044145 is a deficient number, since it is larger than the sum of its proper divisors (3027546079375).
15112253044145 is an equidigital number, since it uses as much as digits as its factorization.
15112253044145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 849245095.
The product of its (nonzero) digits is 96000, while the sum is 38.
Adding to 15112253044145 its reverse (54144035221151), we get a palindrome (69256288265296).
The spelling of 15112253044145 in words is "fifteen trillion, one hundred twelve billion, two hundred fifty-three million, forty-four thousand, one hundred forty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •