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1550113 = 8917417
BaseRepresentation
bin101111010011100100001
32220202100121
411322130201
5344100423
653120241
716114165
oct5723441
92822317
101550113
11969694
12629081
13423736
142c4ca5
1520945d
hex17a721

1550113 has 4 divisors (see below), whose sum is σ = 1567620. Its totient is φ = 1532608.

The previous prime is 1550099. The next prime is 1550119. The reversal of 1550113 is 3110551.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3110551 = 11327527.

It can be written as a sum of positive squares in 2 ways, for example, as 937024 + 613089 = 968^2 + 783^2 .

It is a cyclic number.

It is not a de Polignac number, because 1550113 - 213 = 1541921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1550119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8620 + ... + 8797.

It is an arithmetic number, because the mean of its divisors is an integer number (391905).

21550113 is an apocalyptic number.

It is an amenable number.

1550113 is a deficient number, since it is larger than the sum of its proper divisors (17507).

1550113 is an equidigital number, since it uses as much as digits as its factorization.

1550113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17506.

The product of its (nonzero) digits is 75, while the sum is 16.

The square root of 1550113 is about 1245.0353408639. The cubic root of 1550113 is about 115.7322650081.

Adding to 1550113 its reverse (3110551), we get a palindrome (4660664).

The spelling of 1550113 in words is "one million, five hundred fifty thousand, one hundred thirteen".

Divisors: 1 89 17417 1550113