Base | Representation |
---|---|
bin | 10111101001110010001… |
… | …111101001011111000001 |
3 | 12202101110220211211222011 |
4 | 113221302033221133001 |
5 | 203112322032430333 |
6 | 3242412142212521 |
7 | 225301165644226 |
oct | 27516217513701 |
9 | 5671426754864 |
10 | 1625414342593 |
11 | 577375027208 |
12 | 223023b84141 |
13 | ba378253192 |
14 | 58955acd94d |
15 | 2c43284e9cd |
hex | 17a723e97c1 |
1625414342593 has 2 divisors, whose sum is σ = 1625414342594. Its totient is φ = 1625414342592.
The previous prime is 1625414342533. The next prime is 1625414342623. The reversal of 1625414342593 is 3952434145261.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1536429662784 + 88984679809 = 1239528^2 + 298303^2 .
It is a cyclic number.
It is not a de Polignac number, because 1625414342593 - 217 = 1625414211521 is a prime.
It is not a weakly prime, because it can be changed into another prime (1625414342533) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 812707171296 + 812707171297.
It is an arithmetic number, because the mean of its divisors is an integer number (812707171297).
Almost surely, 21625414342593 is an apocalyptic number.
It is an amenable number.
1625414342593 is a deficient number, since it is larger than the sum of its proper divisors (1).
1625414342593 is an equidigital number, since it uses as much as digits as its factorization.
1625414342593 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3110400, while the sum is 49.
The spelling of 1625414342593 in words is "one trillion, six hundred twenty-five billion, four hundred fourteen million, three hundred forty-two thousand, five hundred ninety-three".
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