Base | Representation |
---|---|
bin | 1110111011110111101001… |
… | …1111101111001001000001 |
3 | 2011010220022120011012000211 |
4 | 3232331322133233021001 |
5 | 4123023133032100023 |
6 | 54532010510314121 |
7 | 3313300260230434 |
oct | 356757237571101 |
9 | 64126276135024 |
10 | 16421715112513 |
11 | 5261457082247 |
12 | 1a1277b1b8941 |
13 | 92173a93c449 |
14 | 40ab5b0a381b |
15 | 1d7276dcba0d |
hex | eef7a7ef241 |
16421715112513 has 8 divisors (see below), whose sum is σ = 16442117340480. Its totient is φ = 16401313859760.
The previous prime is 16421715112511. The next prime is 16421715112553. The reversal of 16421715112513 is 31521151712461.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 16421715112513 - 21 = 16421715112511 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (16421715112511) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 36976308 + ... + 37417786.
It is an arithmetic number, because the mean of its divisors is an integer number (2055264667560).
Almost surely, 216421715112513 is an apocalyptic number.
It is an amenable number.
16421715112513 is a deficient number, since it is larger than the sum of its proper divisors (20402227967).
16421715112513 is an equidigital number, since it uses as much as digits as its factorization.
16421715112513 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 487607.
The product of its digits is 50400, while the sum is 40.
Adding to 16421715112513 its reverse (31521151712461), we get a palindrome (47942866824974).
The spelling of 16421715112513 in words is "sixteen trillion, four hundred twenty-one billion, seven hundred fifteen million, one hundred twelve thousand, five hundred thirteen".
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