1644414113 has 2 divisors, whose sum is σ = 1644414114. Its totient is φ = 1644414112.

The previous prime is 1644414103. The next prime is 1644414143. The reversal of 1644414113 is 3114144461.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1632806464 + 11607649 = 40408^2 + 3407^2 .

It is an emirp because it is prime and its reverse (3114144461) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1644414113 - 2⁸ = 1644413857 is a prime.

It is a super-3 number, since 3×1644414113³ (a number of 29 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (1644414103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 822207056 + 822207057.

It is an arithmetic number, because the mean of its divisors is an integer number (822207057).

It is a self-describing number.

Almost surely, 2^1644414113 is an apocalyptic number.

It is an amenable number.

1644414113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1644414113 is an equidigital number, since it uses as much as digits as its factorization.

1644414113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4608, while the sum is 29.

The square root of 1644414113 is about 40551.3762158573. The cubic root of 1644414113 is about 1180.3307779465.

Adding to 1644414113 its reverse (3114144461), we get a palindrome (4758558574).

The spelling of 1644414113 in words is "one billion, six hundred forty-four million, four hundred fourteen thousand, one hundred thirteen".