Base | Representation |
---|---|
bin | 1111000011000101100111… |
… | …0001101010101101111011 |
3 | 2011120202101200122011020212 |
4 | 3300301121301222231323 |
5 | 4132041113333411233 |
6 | 55104555434141335 |
7 | 3325250241224615 |
oct | 360613161525573 |
9 | 64522350564225 |
10 | 16545720216443 |
11 | 52aa000797210 |
12 | 1a3280828184b |
13 | 9303408143a2 |
14 | 412b622cbdb5 |
15 | 1da5d37b4a48 |
hex | f0c59c6ab7b |
16545720216443 has 8 divisors (see below), whose sum is σ = 18058346769216. Its totient is φ = 15034505358600.
The previous prime is 16545720216439. The next prime is 16545720216449. The reversal of 16545720216443 is 34461202754561.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 16545720216443 - 22 = 16545720216439 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 16545720216391 and 16545720216400.
It is not an unprimeable number, because it can be changed into a prime (16545720216449) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 352899221 + ... + 352946102.
It is an arithmetic number, because the mean of its divisors is an integer number (2257293346152).
Almost surely, 216545720216443 is an apocalyptic number.
16545720216443 is a deficient number, since it is larger than the sum of its proper divisors (1512626552773).
16545720216443 is a wasteful number, since it uses less digits than its factorization.
16545720216443 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 705847465.
The product of its (nonzero) digits is 4838400, while the sum is 50.
The spelling of 16545720216443 in words is "sixteen trillion, five hundred forty-five billion, seven hundred twenty million, two hundred sixteen thousand, four hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •