Base | Representation |
---|---|
bin | 1111011001010000110011… |
… | …1101100010101101111001 |
3 | 2012221011201200101211220121 |
4 | 3312110030331202231321 |
5 | 4204311321443314423 |
6 | 100000002221053241 |
7 | 3364624666305016 |
oct | 366241475425571 |
9 | 65834650354817 |
10 | 16926683573113 |
11 | 5436625665726 |
12 | 1a946080b7221 |
13 | 95a244225222 |
14 | 4273820d870d |
15 | 1e547dcd645d |
hex | f650cf62b79 |
16926683573113 has 2 divisors, whose sum is σ = 16926683573114. Its totient is φ = 16926683573112.
The previous prime is 16926683573089. The next prime is 16926683573117. The reversal of 16926683573113 is 31137538662961.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 16751928639744 + 174754933369 = 4092912^2 + 418037^2 .
It is a cyclic number.
It is not a de Polignac number, because 16926683573113 - 241 = 14727660317561 is a prime.
It is not a weakly prime, because it can be changed into another prime (16926683573117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8463341786556 + 8463341786557.
It is an arithmetic number, because the mean of its divisors is an integer number (8463341786557).
Almost surely, 216926683573113 is an apocalyptic number.
It is an amenable number.
16926683573113 is a deficient number, since it is larger than the sum of its proper divisors (1).
16926683573113 is an equidigital number, since it uses as much as digits as its factorization.
16926683573113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 29393280, while the sum is 61.
The spelling of 16926683573113 in words is "sixteen trillion, nine hundred twenty-six billion, six hundred eighty-three million, five hundred seventy-three thousand, one hundred thirteen".
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