Base | Representation |
---|---|
bin | 110010100011000… |
… | …1110010111101001 |
3 | 11101012120100200112 |
4 | 1211012032113221 |
5 | 11433202134122 |
6 | 440145544105 |
7 | 60013604663 |
oct | 14506162751 |
9 | 4335510615 |
10 | 1696130537 |
11 | 7a046aa82 |
12 | 3b4045035 |
13 | 21052324a |
14 | 121399533 |
15 | 9dd8c2e2 |
hex | 6518e5e9 |
1696130537 has 4 divisors (see below), whose sum is σ = 1696646736. Its totient is φ = 1695614340.
The previous prime is 1696130533. The next prime is 1696130543. The reversal of 1696130537 is 7350316961.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1696130537 - 22 = 1696130533 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1696130494 and 1696130503.
It is not an unprimeable number, because it can be changed into a prime (1696130533) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 253139 + ... + 259752.
It is an arithmetic number, because the mean of its divisors is an integer number (424161684).
Almost surely, 21696130537 is an apocalyptic number.
It is an amenable number.
1696130537 is a deficient number, since it is larger than the sum of its proper divisors (516199).
1696130537 is an equidigital number, since it uses as much as digits as its factorization.
1696130537 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 516198.
The product of its (nonzero) digits is 102060, while the sum is 41.
The square root of 1696130537 is about 41184.1053927362. The cubic root of 1696130537 is about 1192.5769865634.
The spelling of 1696130537 in words is "one billion, six hundred ninety-six million, one hundred thirty thousand, five hundred thirty-seven".
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