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172581113 is a prime number
BaseRepresentation
bin10100100100101…
…10000011111001
3110000202000210002
422102112003321
5323140043423
625043002345
74163625635
oct1222260371
9400660702
10172581113
1189465821
12499693b5
13299a7103
1418cc5dc5
1510240228
hexa4960f9

172581113 has 2 divisors, whose sum is σ = 172581114. Its totient is φ = 172581112.

The previous prime is 172581107. The next prime is 172581131. The reversal of 172581113 is 311185271.

Together with next prime (172581131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 167754304 + 4826809 = 12952^2 + 2197^2 .

It is an emirp because it is prime and its reverse (311185271) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 172581113 - 214 = 172564729 is a prime.

It is not a weakly prime, because it can be changed into another prime (172581163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 86290556 + 86290557.

It is an arithmetic number, because the mean of its divisors is an integer number (86290557).

Almost surely, 2172581113 is an apocalyptic number.

It is an amenable number.

172581113 is a deficient number, since it is larger than the sum of its proper divisors (1).

172581113 is an equidigital number, since it uses as much as digits as its factorization.

172581113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1680, while the sum is 29.

The square root of 172581113 is about 13137.0130927848. The cubic root of 172581113 is about 556.7553793063.

The spelling of 172581113 in words is "one hundred seventy-two million, five hundred eighty-one thousand, one hundred thirteen".