Base | Representation |
---|---|
bin | 11100011100101000110… |
… | …001000001011001110001 |
3 | 20220212220221001122100011 |
4 | 130130220301001121301 |
5 | 224012110334342441 |
6 | 4054022124054521 |
7 | 261144045222163 |
oct | 34345061013161 |
9 | 6825827048304 |
10 | 1954894059121 |
11 | 69407a8068a3 |
12 | 276a56094441 |
13 | 11246570c623 |
14 | 6a890124933 |
15 | 35cb8114581 |
hex | 1c728c41671 |
1954894059121 has 2 divisors, whose sum is σ = 1954894059122. Its totient is φ = 1954894059120.
The previous prime is 1954894059113. The next prime is 1954894059137. The reversal of 1954894059121 is 1219504984591.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1837271811600 + 117622247521 = 1355460^2 + 342961^2 .
It is a cyclic number.
It is not a de Polignac number, because 1954894059121 - 23 = 1954894059113 is a prime.
It is a super-2 number, since 2×19548940591212 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1954894059191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 977447029560 + 977447029561.
It is an arithmetic number, because the mean of its divisors is an integer number (977447029561).
Almost surely, 21954894059121 is an apocalyptic number.
It is an amenable number.
1954894059121 is a deficient number, since it is larger than the sum of its proper divisors (1).
1954894059121 is an equidigital number, since it uses as much as digits as its factorization.
1954894059121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4665600, while the sum is 58.
The spelling of 1954894059121 in words is "one trillion, nine hundred fifty-four billion, eight hundred ninety-four million, fifty-nine thousand, one hundred twenty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •