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19683 = 39
BaseRepresentation
bin100110011100011
31000000000
410303203
51112213
6231043
7111246
oct46343
930000
1019683
1113874
12b483
138c61
14725d
155c73
hex4ce3

19683 has 10 divisors (see below), whose sum is σ = 29524. Its totient is φ = 13122.

The previous prime is 19681. The next prime is 19687. The reversal of 19683 is 38691.

Multipling 19683 by its sum of digits (27), we get a 12-th power (531441 = 312).

19683 divided by its sum of digits (27) gives a 6-th power (729 = 36).

The cubic root of 19683 is 27.

It is a perfect power (a cube, a 9-th power), and thus also a powerful number.

It is not a de Polignac number, because 19683 - 21 = 19681 is a prime.

It is a Smith number, since the sum of its digits (27) coincides with the sum of the digits of its prime factors.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is an Ulam number.

It is a Duffinian number.

Its product of digits (1296) is a multiple of the sum of its prime divisors (3).

It is a plaindrome in base 7.

It is a nialpdrome in base 3 and base 9.

It is not an unprimeable number, because it can be changed into a prime (19681) by changing a digit.

It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 6560 + 6561 + 6562.

19683 is a Friedman number, since it can be written as ((8*3)/6-1)^9, using all its digits and the basic arithmetic operations.

219683 is an apocalyptic number.

19683 is a deficient number, since it is larger than the sum of its proper divisors (9841).

19683 is an frugal number, since it uses more digits than its factorization.

19683 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 27 (or 3 counting only the distinct ones).

The product of its digits is 1296, while the sum is 27.

The square root of 19683 is about 140.2961154131.

The spelling of 19683 in words is "nineteen thousand, six hundred eighty-three".

Divisors: 1 3 9 27 81 243 729 2187 6561 19683