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199880953 is a prime number
BaseRepresentation
bin10111110100111…
…11000011111001
3111221010000010021
423322133003321
5402132142303
631500050441
74644650206
oct1372370371
9457100107
10199880953
11a2911578
1256b33a21
133254506c
1512833ebd
hexbe9f0f9

199880953 has 2 divisors, whose sum is σ = 199880954. Its totient is φ = 199880952.

The previous prime is 199880929. The next prime is 199880977. The reversal of 199880953 is 359088991.

It is a balanced prime because it is at equal distance from previous prime (199880929) and next prime (199880977).

It can be written as a sum of positive squares in only one way, i.e., 138227049 + 61653904 = 11757^2 + 7852^2 .

It is a cyclic number.

It is not a de Polignac number, because 199880953 - 221 = 197783801 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 199880953.

It is not a weakly prime, because it can be changed into another prime (199880983) by changing a digit.

It is a good prime.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 99940476 + 99940477.

It is an arithmetic number, because the mean of its divisors is an integer number (99940477).

Almost surely, 2199880953 is an apocalyptic number.

It is an amenable number.

199880953 is a deficient number, since it is larger than the sum of its proper divisors (1).

199880953 is an equidigital number, since it uses as much as digits as its factorization.

199880953 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 699840, while the sum is 52.

The square root of 199880953 is about 14137.9260501673. The cubic root of 199880953 is about 584.6874927663.

The spelling of 199880953 in words is "one hundred ninety-nine million, eight hundred eighty thousand, nine hundred fifty-three".