Base | Representation |
---|---|
bin | 10111110100111… |
… | …11000100010111 |
3 | 111221010000011101 |
4 | 23322133010113 |
5 | 402132142413 |
6 | 31500050531 |
7 | 4644650251 |
oct | 1372370427 |
9 | 457100141 |
10 | 199880983 |
11 | a29115a5 |
12 | 56b33a47 |
13 | 32545093 |
14 | 1c790cd1 |
15 | 12833edd |
hex | be9f117 |
199880983 has 2 divisors, whose sum is σ = 199880984. Its totient is φ = 199880982.
The previous prime is 199880977. The next prime is 199880999. The reversal of 199880983 is 389088991.
It is a weak prime.
It is an emirp because it is prime and its reverse (389088991) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 199880983 - 217 = 199749911 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (199880953) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 99940491 + 99940492.
It is an arithmetic number, because the mean of its divisors is an integer number (99940492).
Almost surely, 2199880983 is an apocalyptic number.
199880983 is a deficient number, since it is larger than the sum of its proper divisors (1).
199880983 is an equidigital number, since it uses as much as digits as its factorization.
199880983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1119744, while the sum is 55.
The square root of 199880983 is about 14137.9271111433. The cubic root of 199880983 is about 584.6875220181.
The spelling of 199880983 in words is "one hundred ninety-nine million, eight hundred eighty thousand, nine hundred eighty-three".
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