Search a number
-
+
19991220001 is a prime number
BaseRepresentation
bin10010100111100100…
…011100111100100001
31220121020000012100121
4102213210130330201
5311420223020001
613103413120241
71305254365144
oct224744347441
956536005317
1019991220001
118529582525
123a5b029081
131b6792247c
14d7907c05b
157c00d46a1
hex4a791cf21

19991220001 has 2 divisors, whose sum is σ = 19991220002. Its totient is φ = 19991220000.

The previous prime is 19991219933. The next prime is 19991220013. The reversal of 19991220001 is 10002219991.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 18482674401 + 1508545600 = 135951^2 + 38840^2 .

It is an emirp because it is prime and its reverse (10002219991) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 19991220001 - 219 = 19990695713 is a prime.

It is not a weakly prime, because it can be changed into another prime (19991220031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9995610000 + 9995610001.

It is an arithmetic number, because the mean of its divisors is an integer number (9995610001).

Almost surely, 219991220001 is an apocalyptic number.

It is an amenable number.

19991220001 is a deficient number, since it is larger than the sum of its proper divisors (1).

19991220001 is an equidigital number, since it uses as much as digits as its factorization.

19991220001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2916, while the sum is 34.

Adding to 19991220001 its reverse (10002219991), we get a palindrome (29993439992).

The spelling of 19991220001 in words is "nineteen billion, nine hundred ninety-one million, two hundred twenty thousand, one".