Base | Representation |
---|---|
bin | 100110001000… |
… | …1001001000000 |
3 | 1101121202110010 |
4 | 1030101021000 |
5 | 20104240102 |
6 | 1552304520 |
7 | 331640034 |
oct | 114211100 |
9 | 41552403 |
10 | 19993152 |
11 | 10316173 |
12 | 6842140 |
13 | 41b028a |
14 | 29261c4 |
15 | 1b4dd6c |
hex | 1311240 |
19993152 has 56 divisors (see below), whose sum is σ = 53474112. Its totient is φ = 6592000.
The previous prime is 19993097. The next prime is 19993157. The reversal of 19993152 is 25139991.
19993152 is nontrivially palindromic in base 5.
It is a super-2 number, since 2×199931522 = 799452253790208, which contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 19993152.
It is not an unprimeable number, because it can be changed into a prime (19993157) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (7) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 18877 + ... + 19907.
Almost surely, 219993152 is an apocalyptic number.
19993152 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 19993152, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (26737056).
19993152 is an abundant number, since it is smaller than the sum of its proper divisors (33480960).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
19993152 is a wasteful number, since it uses less digits than its factorization.
19993152 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1147 (or 1137 counting only the distinct ones).
The product of its digits is 21870, while the sum is 39.
The square root of 19993152 is about 4471.3702597750. The cubic root of 19993152 is about 271.4107775698.
It can be divided in two parts, 1999 and 3152, that added together give a triangular number (5151 = T101).
The spelling of 19993152 in words is "nineteen million, nine hundred ninety-three thousand, one hundred fifty-two".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •