19997000113 has 4 divisors (see below), whose sum is σ = 19997358948. Its totient is φ = 19996641280.

The previous prime is 19997000099. The next prime is 19997000137. The reversal of 19997000113 is 31100079991.

19997000113 = 99992² + 99993².

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 31100079991 = 199 ⋅156281809.

It can be written as a sum of positive squares in 2 ways, for example, as 9998600049 + 9998400064 = 99993^2 + 99992^2 .

It is a cyclic number.

It is not a de Polignac number, because 19997000113 - 2⁹ = 19996999601 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (19997000173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 75928 + ... + 213913.

It is an arithmetic number, because the mean of its divisors is an integer number (4999339737).

Almost surely, 2^19997000113 is an apocalyptic number.

19997000113 is the 99993-rd centered square number.

It is an amenable number.

19997000113 is a deficient number, since it is larger than the sum of its proper divisors (358835).

19997000113 is an equidigital number, since it uses as much as digits as its factorization.

19997000113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 358834.

The product of its (nonzero) digits is 15309, while the sum is 40.

The spelling of 19997000113 in words is "nineteen billion, nine hundred ninety-seven million, one hundred thirteen", and thus it is an aban number.