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19999963 is a prime number
BaseRepresentation
bin100110001001…
…0110011011011
31101122002210101
41030102303123
520104444323
61552400231
7331665634
oct114226333
941562711
1019999963
11103202a5
126846077
1341b33c9
14292888b
151b50dad
hex1312cdb

19999963 has 2 divisors, whose sum is σ = 19999964. Its totient is φ = 19999962.

The previous prime is 19999927. The next prime is 19999981. The reversal of 19999963 is 36999991.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-19999963 is a prime.

It is not a weakly prime, because it can be changed into another prime (19999663) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9999981 + 9999982.

It is an arithmetic number, because the mean of its divisors is an integer number (9999982).

Almost surely, 219999963 is an apocalyptic number.

19999963 is a deficient number, since it is larger than the sum of its proper divisors (1).

19999963 is an equidigital number, since it uses as much as digits as its factorization.

19999963 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1062882, while the sum is 55.

The square root of 19999963 is about 4472.1318182719. The cubic root of 19999963 is about 271.4415942703.

The spelling of 19999963 in words is "nineteen million, nine hundred ninety-nine thousand, nine hundred sixty-three".