Base | Representation |
---|---|
bin | 11101000110101111111… |
… | …110001111000100101001 |
3 | 21002012122020211010211120 |
4 | 131012233332033010221 |
5 | 230232212200320410 |
6 | 4130501104045453 |
7 | 264334433336601 |
oct | 35065776170451 |
9 | 7065566733746 |
10 | 2000112120105 |
11 | 701274170330 |
12 | 283775603889 |
13 | 1167c085c728 |
14 | 6cb3d717c01 |
15 | 37062c78570 |
hex | 1d1aff8f129 |
2000112120105 has 64 divisors (see below), whose sum is σ = 3519823507200. Its totient is φ = 961802726400.
The previous prime is 2000112120103. The next prime is 2000112120109. The reversal of 2000112120105 is 5010212110002.
It is not a de Polignac number, because 2000112120105 - 21 = 2000112120103 is a prime.
It is a super-3 number, since 3×20001121201053 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is not an unprimeable number, because it can be changed into a prime (2000112120103) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 11049871 + ... + 11229419.
It is an arithmetic number, because the mean of its divisors is an integer number (54997242300).
Almost surely, 22000112120105 is an apocalyptic number.
It is an amenable number.
2000112120105 is a deficient number, since it is larger than the sum of its proper divisors (1519711387095).
2000112120105 is a wasteful number, since it uses less digits than its factorization.
2000112120105 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 180122.
The product of its (nonzero) digits is 40, while the sum is 15.
Adding to 2000112120105 its reverse (5010212110002), we get a palindrome (7010324230107).
The spelling of 2000112120105 in words is "two trillion, one hundred twelve million, one hundred twenty thousand, one hundred five".
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