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2000112120113 is a prime number
BaseRepresentation
bin11101000110101111111…
…110001111000100110001
321002012122020211010211212
4131012233332033010301
5230232212200320423
64130501104045505
7264334433336612
oct35065776170461
97065566733755
102000112120113
11701274170338
12283775603895
131167c085c733
146cb3d717c09
1537062c78578
hex1d1aff8f131

2000112120113 has 2 divisors, whose sum is σ = 2000112120114. Its totient is φ = 2000112120112.

The previous prime is 2000112120109. The next prime is 2000112120157. The reversal of 2000112120113 is 3110212110002.

Adding to 2000112120113 its reverse (3110212110002), we get a palindrome (5110324230115).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1919130896929 + 80981223184 = 1385327^2 + 284572^2 .

It is a cyclic number.

It is not a de Polignac number, because 2000112120113 - 22 = 2000112120109 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (2000112120103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000056060056 + 1000056060057.

It is an arithmetic number, because the mean of its divisors is an integer number (1000056060057).

Almost surely, 22000112120113 is an apocalyptic number.

It is an amenable number.

2000112120113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2000112120113 is an equidigital number, since it uses as much as digits as its factorization.

2000112120113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 14.

The spelling of 2000112120113 in words is "two trillion, one hundred twelve million, one hundred twenty thousand, one hundred thirteen".