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2000133100241 is a prime number
BaseRepresentation
bin11101000110110001001…
…110010001001011010001
321002012200201022001011122
4131012301032101023101
5230232233033201431
64130503133452025
7264335106560303
oct35066116211321
97065621261148
102000133100241
11701284a9aa91
12283780641015
131167c4cc7003
146cb42419973
1537064a1ea7b
hex1d1b13912d1

2000133100241 has 2 divisors, whose sum is σ = 2000133100242. Its totient is φ = 2000133100240.

The previous prime is 2000133100181. The next prime is 2000133100243. The reversal of 2000133100241 is 1420013310002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1996792260241 + 3340840000 = 1413079^2 + 57800^2 .

It is a cyclic number.

It is not a de Polignac number, because 2000133100241 - 234 = 1982953231057 is a prime.

Together with 2000133100243, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (2000133100243) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000066550120 + 1000066550121.

It is an arithmetic number, because the mean of its divisors is an integer number (1000066550121).

Almost surely, 22000133100241 is an apocalyptic number.

It is an amenable number.

2000133100241 is a deficient number, since it is larger than the sum of its proper divisors (1).

2000133100241 is an equidigital number, since it uses as much as digits as its factorization.

2000133100241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 2000133100241 its reverse (1420013310002), we get a palindrome (3420146410243).

The spelling of 2000133100241 in words is "two trillion, one hundred thirty-three million, one hundred thousand, two hundred forty-one".